TheWrathOfMath
Junior Member
- Joined
- Mar 31, 2022
- Messages
- 162
Then I suppose that the basis is (8,1,0,0) and the dimension is 4? Is that right?I like you second suggestion better than the first, if only because the first refers to vectors in [imath]\mathbb R^2[/imath], but you need [imath]\mathbb R^4[/imath].
So what is the dimension of the subspace?
And the basis?
No, not right yet. I agree that (8,1,0,0) can be used as a basis vector, but how many (linearly independent) basis vectors are there in your subspace?Then I suppose that the basis is (8,1,0,0) and the dimension is 4? Is that right?
Please excuse me for the idiotic error. The dimension is one since there is only one vector.No, not right yet. I agree that (8,1,0,0) can be used as a basis vector, but how many (linearly independent) basis vectors are there in your subspace?