bmartin2389
New member
- Joined
- Aug 27, 2012
- Messages
- 1
Hey everyone,
So it has been quite awhile since I've taken some math courses but I'm getting into calculus and I was needing some help with a problem I have regarding limits. My main question is
how does the lim 1 as x approaches 0 equal -1?
Here is the full question including work I have already completed.
f(x) = -e^-x if x does not equal 0
1 if x=0 and a=0
find the limit of f(x) from the right and left of the function and graph.
My answers so far:
lim -e^-x = -1
x approaches 0-
The book says for the limit of 1 that the answer is equal to -1, my question is how do they get that answer? I thought if the function was a constant, then the answer to the limit was the constant? or
lim c = c
x approaches a
Maybe its different with piece wise functions? any help is appreciated
So it has been quite awhile since I've taken some math courses but I'm getting into calculus and I was needing some help with a problem I have regarding limits. My main question is
how does the lim 1 as x approaches 0 equal -1?
Here is the full question including work I have already completed.
f(x) = -e^-x if x does not equal 0
1 if x=0 and a=0
find the limit of f(x) from the right and left of the function and graph.
My answers so far:
lim -e^-x = -1
x approaches 0-
The book says for the limit of 1 that the answer is equal to -1, my question is how do they get that answer? I thought if the function was a constant, then the answer to the limit was the constant? or
lim c = c
x approaches a
Maybe its different with piece wise functions? any help is appreciated