The best thing you can do with these sort of questions is "get to know" the powers of 2, 3 and 5.
ie, \(\displaystyle 2^0=1, 2^1=1, 2^2=4, 2^3=8, 2^4=16, 2^5= 32, 2^6=64, 2^7=128, 2^8=256, 2^9=512, 2^{10}=1024\)
\(\displaystyle 3^0=1, 3^1=3, 3^2=9, 3^3=27, 3^4=81, 3^5=243\)
\(\displaystyle 5^0=1, 5^2=25, 5^3=125, 5^4=625\) for starters.
The first "thing" I see when looking at (d) is that all the bases can be written in terms of 3s and 5s. That's because I know that \(\displaystyle 3^3=27\), and \(\displaystyle 5^3=125\). If you don't know those basic facts, these questions are so much more difficult. Take the time to make those numbers your friends!
I used to tell my students to write the above on a big piece of paper, paste it up in the toilet, and look at it every day!!
So the first thing to do is replace 27 with (\(\displaystyle 3^3)\) and 125 with (\(\displaystyle 5^3)\) which is what you attempted to do. Brackets are very important.
Now show us what you can do.