Circular measure: A sector OAC subtended at O with radius 15 cm...

[NinaLy]

A sector OAC subtended at O with radius 15 cm as shown in the figure above. Given length of AB is 12 cm, OB is 9 cm and AB is perpendicular to OC.
Find
i) the angle AOC in radian (2 marks)
ii) the area of the shaded region (3 marks)

 

[blamocur]

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[Dr.Peterson]

View attachment 35032
A sector OAC subtended at O with radius 15 cm as shown in the figure above. Given length of AB is 12 cm, OB is 9 cm and AB is perpendicular to OC.
Find
i) the angle AOC in radian (2 marks)
ii) the area of the shaded region (3 marks)

You might want to first redraw the picture so that the arc looks more like its center is at O; that will help you see things right.

Then show us what ideas you have.

 

[NinaLy]

You might want to first redraw the picture so that the arc looks more like its center is at O; that will help you see things right.

Then show us what ideas you have.

 

[NinaLy]

You might want to first redraw the picture so that the arc looks more like its center is at O; that will help you see things right.

Then show us what ideas you have.

I'm sorry but that's as far I can go. I do know the radius is 15 but I have no idea how to correlate any equations to find the angle

 

[topsquark]

I'm sorry but that's as far I can go. I do know the radius is 15 but I have no idea how to correlate any equations to find the angle

Hint: What's the tangent of angle AOC?

-Dan

 

[NinaLy]

Hint: What's the tangent of angle AOC?

-Dan

but how do I find the tangent? I'm clueless

 

[topsquark]

but how do I find the tangent? I'm clueless

See here.

-Dan

 

[pka]

Notation: the length of a line-segment: [imath]\ell(\overline{AB})=12[/imath]
So that [imath]m(\angle AOC)=\arctan\left(\dfrac{\ell(\overline{AB})}{\ell(\overline{BO)}}\right)[/imath]
SEE THIS

[imath][/imath][imath][/imath][imath][/imath][imath][/imath]imath][/imath]

 

[NinaLy]

See here.

-Dan

THANK YOUUU

 

[NinaLy]

Notation: the length of a line-segment: [imath]\ell(\overline{AB})=12[/imath]
So that [imath]m(\angle AOC)=\arctan\left(\dfrac{\ell(\overline{AB})}{\ell(\overline{BO)}}\right)[/imath]
SEE THIS

[imath][/imath][imath][/imath][imath][/imath][imath][/imath]imath][/imath]

thank you very muchhh!

 

[MarkFL]

What is the relationship between the area of the triangle, the shaded area, and the area of the sector?