I am in doubt there. Why does the number 2 is enclosed in brackets here?. Don't understand that.What is {2}? A number?
Two of those are correct and two are incorrect!Hi, I need your conformation of this solution.
consider the following set of numbers:
A={0,3,−3,2,1,{2}}
which of the following is true?
- 4 ∈ A false
- 2 ∉ A false
- {3} ∈ A true
- {2}∈ A true
thanks, eddy
Why does the number 2 is enclosed in brackets here?. Don't understand that. what does it mean?Two of those are correct and two are incorrect!
how about a set with a single number, since it is enclosed in brackets. that is the only one explanation for those brackets around 2.What is {2}? A number?
I agree that '{2}' means a set with a single member 2.how about a set with a single number, since it is enclosed in brackets. that is the only one explanation for those brackets around 2.
well, 4 definitely does not belong in the set. that is one correct.Two of those are correct and two are incorrect!
well, then, after blamocur's confirmation then {2} does not belong either. Because it is a set in and of itself.I agree that '{2}' means a set with a single member 2.
The notation {2} means that the set containing 2 is an element of the set -- so technically they are wrong in calling this a "set of numbers"! It is a set containing some numbers and a set.Hi, I need your conformation of this solution.
consider the following set of numbers:
A={0,3,−3,2,1,{2}}
which of the following is true?
- 4 ∈ A false
- 2 ∉ A false
- {3} ∈ A true
- {2}∈ A true
Cannot agree with this one: a set can be a member of another set, not necessarily "in and of itself".well, then, after blamocur's confirmation then {2} does not belong either. Because it is a set in and of itself.
ok, got that.Cannot agree with this one: a set can be a member of another set, not necessarily "in and of itself".
{3} is not an element. good. I got that one wrong. confused on that. Now I see it. Got 3 out of 4!.The notation {2} means that the set containing 2 is an element of the set -- so technically they are wrong in calling this a "set of numbers"! It is a set containing some numbers and a set.
You might think of a set as a bag containing things, and this bag contains a little bag that contains the number 2, along with some "free" numbers that are elements of the set directly.
So:
- 4 is not an element of the set, so the first statement is false. (It is not mentioned at all.)
- 2 is an element of the set, so the second statement is false. (2 is listed both as a free element and as an element of a set.)
- {3} is not an element of the set, so the third statement is false. (3 is an element of the set,
The notation {2} means that the set containing 2 is an element of the set -- so technically they are wrong in calling this a "set of numbers"! It is a set containing some numbers and a set.
You might think of a set as a bag containing things, and this bag contains a little bag that contains the number 2, along with some "free" numbers that are elements of the set directly.
So:
- 4 is not an element of the set, so the first statement is false. (It is not mentioned at all.)
- 2 is an element of the set, so the second statement is false. (2 is listed both as a free element and as an element of a set.)
- {3} is not an element of the set, so the third statement is false. (3 is an element of the set, not of a set inside the set.)
- {2} is an element of the set. so the fourth statement is true. (2 is both an element in its own right, and an element of a contained set.)
- not of a set inside the set.)
- {2} is an element of the set. so the fourth statement is true. (2 is both an element in its own right, and an element of a contained set.)
thank you for the explanation. very helpful!. Merry Christmas if celebrated.The notation {2} means that the set containing 2 is an element of the set -- so technically they are wrong in calling this a "set of numbers"! It is a set containing some numbers and a set.
You might think of a set as a bag containing things, and this bag contains a little bag that contains the number 2, along with some "free" numbers that are elements of the set directly.
So:
- 4 is not an element of the set, so the first statement is false. (It is not mentioned at all.)
- 2 is an element of the set, so the second statement is false. (2 is listed both as a free element and as an element of a set.)
- {3} is not an element of the set, so the third statement is false. (3 is an element of the set, not of a set inside the set.)
- {2} is an element of the set. so the fourth statement is true. (2 is both an element in its own right, and an element of a contained set.)
{3} is not an element. good. I got that one wrong. confused on that. Now I see it. Got 3 out of 4!.
pka you were wrong when you say two correct two wrong!.
Both your statements are wrong.[math]{3}\in A[/math] is false, but [math]{3}\subset A[/math] is true...