harpazo
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Section R.3
Geometry Essentials
Michael Sullivan
Textbook: College Algebra Edition 9
The deck of a destroyer is 100 feet above sea level. How far can a person see from the deck?
A similar question (using different numbers) found online provided the following information:
"The mathematically correct formula is d^2 = 2*r*h where d is the distance to the horizon, r is the radius of the earth, and h is the height above sea level, all in the same units."
Hint Provided by Sullivan:
Earth's radius = 3960 miles
I basically plug and chug.
d^2 = 2(3690)(100)
d^2 = 792,000
sqrt{d^2} = sqrt{792,000}
d = 889.9438184515
My answer is as follows:
A person standing on the deck of a destroyer 100 feet above sea level can see about 889.94 feet. What do you say?
Geometry Essentials
Michael Sullivan
Textbook: College Algebra Edition 9
The deck of a destroyer is 100 feet above sea level. How far can a person see from the deck?
A similar question (using different numbers) found online provided the following information:
"The mathematically correct formula is d^2 = 2*r*h where d is the distance to the horizon, r is the radius of the earth, and h is the height above sea level, all in the same units."
Hint Provided by Sullivan:
Earth's radius = 3960 miles
I basically plug and chug.
d^2 = 2(3690)(100)
d^2 = 792,000
sqrt{d^2} = sqrt{792,000}
d = 889.9438184515
My answer is as follows:
A person standing on the deck of a destroyer 100 feet above sea level can see about 889.94 feet. What do you say?