Integrate
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- May 17, 2018
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1.) dy/dx -5y =(-5/2) * x
2.) y^ -3 * dy/dx-5y^ -2=(-5/2) * x
3.) v=y^-2
4.) dv/dx=-2y^ -3 * dy/dx
Shouldn't y^-2 go to zero since there is no x in this expression?
Something I remember from implicit differentiation is that when we say "respect to" it means we are trying to find the relation of rate of change between variables dependent on each other.
Is that how I should see it here?
2.) y^ -3 * dy/dx-5y^ -2=(-5/2) * x
3.) v=y^-2
4.) dv/dx=-2y^ -3 * dy/dx
Shouldn't y^-2 go to zero since there is no x in this expression?
Something I remember from implicit differentiation is that when we say "respect to" it means we are trying to find the relation of rate of change between variables dependent on each other.
Is that how I should see it here?
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