Equation help

Audentes

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Jun 8, 2020
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I got #2 on some tries and #4 on the others. Could someone tell me the answer? thanks
 

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Let’s work it out

[MATH]3(x^2 + 2x - 3 ) - 4(4x^2 - 7x + 5) =\\ 3x^2 + 6x - 9 - 16x^2 + 28x - 20 = \\ x^2(3 - 16) + x(6 + 28) - (9 + 20) =\\ -13x^2 + 34x - 29.[/MATH]How do you check your answer for this type of problem?
 
Let’s work it out

[MATH]3(x^2 + 2x - 3 ) - 4(4x^2 - 7x + 5) =\\ 3x^2 + 6x - 9 - 16x^2 + 28x - 20 = \\ x^2(3 - 16) + x(6 + 28) - (9 + 20) =\\ -13x^2 + 34x - 29.[/MATH]How do you check your answer for this type of problem?
Substitute x With a number. If x is 1: Both=-8
 
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