Please post your solution.I got #2 on some tries and #4 on the others. Could someone tell me the answer? thanks
Sorry if a bit low qualityPlease post your solution.
Substitute x With a number. If x is 1: Both=-8Let’s work it out
[MATH]3(x^2 + 2x - 3 ) - 4(4x^2 - 7x + 5) =\\ 3x^2 + 6x - 9 - 16x^2 + 28x - 20 = \\ x^2(3 - 16) + x(6 + 28) - (9 + 20) =\\ -13x^2 + 34x - 29.[/MATH]How do you check your answer for this type of problem?
This is not a guarantee, but it will work 99 times out of 100.Substitute x With a number. If x is 1: Both=-8