How can I find the equation of this quadratic function [imath]y= ax^{2} + 2x + c[/imath] if I know two points (-2,0) , (3,5) and the value of b which is 2.
Hi Albi. You can subtitute the given (x,y) values and simplify, to obtain two new equations. Solve that system of two equations for a and c.How can I find the [values of a and c in] this quadratic function y=ax^2+2x+c if I know two points (-2,0) , (3,5)
I got two equations [imath]4a +c =0[/imath] and [imath]9a+c= 5[/imath] , I added them up and I got a = 1 and c = -4, but that's not the correct answer since one of the zeros of this equation is -2 but when I substitute a and c into the equation I get [imath]x_{1}= -1-\sqrt{5}[/imath] and [math]x_{2}=-1+ \sqrt{5}[/math]Hi Albi. You can subtitute the given (x,y) values and simplify, to obtain two new equations. Solve that system of two equations for a and c.
Then check your results, by verifying that x=-2 gives y=0 AND x=3 gives y=5.
Please share your efforts. Thank you!
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Those are close, but not correct. Please show your work.I got two equations 4a + c = 0 and 9a + c = 5
Here it is, even though it's incorrect.Those are close, but not correct. Please show your work.
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Your equations are incorrect - after putting in values of x & y.Here it is, even though it's incorrect.
I don't know what I am missing
Now I did it correctly ?y = ax^2 + 2x + c
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