Expressing vectors by vectors a and b

[naomiik]

Hello! I’m not sure how to express these given vectors by vectors a and b. I had tried to solve a few problems but I’m completely lost.

 

[pka]

Please tell exactly with what you are having trouble.
It would help if you could show the diagrams as well as your work.
Can you show the diagram side-by-side with your work?

 

[naomiik]

I

Please tell exactly with what you are having trouble.
It would help if you could show the diagrams as well as your work.
Can you show the diagram side-by-side with your work?

I’ve tried to express the vectors by vectors a and b, but I’m not sure if it is correct. I want somebody to check if I’m at least doing it correctly.
I could make a collage of those photos but the quality would be bad so I just attached the problems and my answers.

 

[Deleted member 4993]

I

I’ve tried to express the vectors by vectors a and b, but I’m not sure if it is correct. I want somebody to check if I’m at least doing it correctly.
I could make a collage of those photos but the quality would be bad so I just attached the problems and my answers.

Use graphical laws of vector addition (polygon).

Show your attempts.

 

[naomiik]

Use graphical laws of vector addition (polygon).

Show your attempts.

 

[Deleted member 4993]

View attachment 24816

Looks like only one unanswered is the vector CE.

Do you have any other information regarding the hexagon ABCDEF - for example is it a regular hexagon (equal sides and equal internal angles?

 

[pka]

You have some fundamental misunderstanding.
If I can follow the diagrams correctly, in the C diagram we are given:
\(\overrightarrow {FA} = \vec{a} = \overrightarrow {DC};\;\;\;\overrightarrow {FE} = \vec{b} = \overrightarrow {BC};\;\;\&\;\;\overrightarrow {ED} = \overrightarrow {AB} \).
So here goes the list in c).
\(\overrightarrow {BC} = \vec{b}\)
\(\overrightarrow {CM} =\overrightarrow {MB}+\vec{b}\)
\(\overrightarrow {AB} =\overrightarrow {BM}+\vec{a}\)
\(\overrightarrow {CE} =\overrightarrow {CD}+\overrightarrow {CD}=-\vec{a}-\overrightarrow {AB}\)