Factor the polynomials

[dancer.chic]

I am struggling with Algebra 2! I don't get these factoring problems. Help with an explanation please!

x^10-X^8

(x + 5)^2 - 8(x + 5)

x^4 - x^3 + x - 1

3x^2 + 10x + 8

 

[Deleted member 4993]

I am struggling with Algebra 2! I don't get these factoring problems. Help with an explanation please!

x^10-X^8

(x + 5)^2 - 8(x + 5)

x^4 - x^3 + x - 1

3x^2 + 10x + 8

Are you familiar with the definition of factors?

Are you familiar with quadratic equation?

Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.

 

[BigGlenntheHeavy]

\(\displaystyle I'll \ do \ (c) \ for \ you, \ then \can \ you \ do \ the \ others?\)

\(\displaystyle x^4-x^3+x-1=grouping \ x^3(x-1)+1(x-1)=(x-1)(x^3+1)=sum \ of \ cubes \ (x-1)(x+1)(x^2-x+1)\)

 

[lookagain]

I am struggling with Algebra 2! I don't get these factoring problems. Help with an explanation please!

x^10-X^8

Make sure you use lower case or upper case consistently, depending, to represent the same variable.

This should be x^10 - x^8, or \(\displaystyle x^{10} - x^8,\) as well as it is to be consistent with your
other expressions' forms (lower case letters for the variables).