How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1
L lukasz New member Joined Oct 19, 2008 Messages 9 Oct 19, 2008 #1 How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1
L lukasz New member Joined Oct 19, 2008 Messages 9 Oct 19, 2008 #2 How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1 ?
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Oct 20, 2008 #3 Re: factoring \(\displaystyle \frac{1}{a^{-1/2}} = a^{1/2}\) or \(\displaystyle \frac{a^{1/2}}{a^{-1/2}}\cdot \frac{a^{1/2}}{a^{1/2}}=\) ??? I'm not sure why you want to factor.
Re: factoring \(\displaystyle \frac{1}{a^{-1/2}} = a^{1/2}\) or \(\displaystyle \frac{a^{1/2}}{a^{-1/2}}\cdot \frac{a^{1/2}}{a^{1/2}}=\) ??? I'm not sure why you want to factor.
A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 852 Oct 20, 2008 #4 Re: Factoring for simplicity let [1+16t^2]=a this is not neccessary but might help. factor [1+16t^2]^1/2 factor a^1/2 multiply by 1=a^1/2 a^(-1/2) a^1/2{a^1/2 a^(-1/2)} a^(1/2+1/2) a^(-1/2) a a^(-1/2) answer Arthur
Re: Factoring for simplicity let [1+16t^2]=a this is not neccessary but might help. factor [1+16t^2]^1/2 factor a^1/2 multiply by 1=a^1/2 a^(-1/2) a^1/2{a^1/2 a^(-1/2)} a^(1/2+1/2) a^(-1/2) a a^(-1/2) answer Arthur
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Oct 20, 2008 #6 Duplicate threads merged.