If x2+3x=10 , x= I CAN'T figure what the problem is.
G girlpower New member Joined Aug 16, 2012 Messages 47 Aug 23, 2012 #1 If x2+3x=10 , x= I CAN'T figure what the problem is.
L Lost souls New member Joined Aug 14, 2012 Messages 45 Aug 24, 2012 #2 girlpower said: If x2+3x=10 , x= I CAN'T figure what the problem is. Click to expand... since this is a factoring problem, lets start with finding the factors. . \(\displaystyle x^2+3x=10\) \(\displaystyle x^2+3x-10=0\) this is of the form\(\displaystyle AX^2+BX+C\) suppose the roots are a and b. \(\displaystyle a+b=B\) \(\displaystyle a*b=A*C\) in this case, \(\displaystyle a+b=3\) \(\displaystyle a*b=-10\) factors are \(\displaystyle (x+a)\) and \(\displaystyle (x+b)\) values for x would be -a and -b.
girlpower said: If x2+3x=10 , x= I CAN'T figure what the problem is. Click to expand... since this is a factoring problem, lets start with finding the factors. . \(\displaystyle x^2+3x=10\) \(\displaystyle x^2+3x-10=0\) this is of the form\(\displaystyle AX^2+BX+C\) suppose the roots are a and b. \(\displaystyle a+b=B\) \(\displaystyle a*b=A*C\) in this case, \(\displaystyle a+b=3\) \(\displaystyle a*b=-10\) factors are \(\displaystyle (x+a)\) and \(\displaystyle (x+b)\) values for x would be -a and -b.
