If x2+3x=10 , x= I CAN'T figure what the problem is.
G girlpower New member Joined Aug 16, 2012 Messages 47 Aug 23, 2012 #1 If x2+3x=10 , x= I CAN'T figure what the problem is.
L Lost souls New member Joined Aug 14, 2012 Messages 45 Aug 24, 2012 #2 girlpower said: If x2+3x=10 , x= I CAN'T figure what the problem is. Click to expand... since this is a factoring problem, lets start with finding the factors. . x2+3x=10\displaystyle x^2+3x=10x2+3x=10 x2+3x−10=0\displaystyle x^2+3x-10=0x2+3x−10=0 this is of the formAX2+BX+C\displaystyle AX^2+BX+CAX2+BX+C suppose the roots are a and b. a+b=B\displaystyle a+b=Ba+b=B a∗b=A∗C\displaystyle a*b=A*Ca∗b=A∗C in this case, a+b=3\displaystyle a+b=3a+b=3 a∗b=−10\displaystyle a*b=-10a∗b=−10 factors are (x+a)\displaystyle (x+a)(x+a) and (x+b)\displaystyle (x+b)(x+b) values for x would be -a and -b.
girlpower said: If x2+3x=10 , x= I CAN'T figure what the problem is. Click to expand... since this is a factoring problem, lets start with finding the factors. . x2+3x=10\displaystyle x^2+3x=10x2+3x=10 x2+3x−10=0\displaystyle x^2+3x-10=0x2+3x−10=0 this is of the formAX2+BX+C\displaystyle AX^2+BX+CAX2+BX+C suppose the roots are a and b. a+b=B\displaystyle a+b=Ba+b=B a∗b=A∗C\displaystyle a*b=A*Ca∗b=A∗C in this case, a+b=3\displaystyle a+b=3a+b=3 a∗b=−10\displaystyle a*b=-10a∗b=−10 factors are (x+a)\displaystyle (x+a)(x+a) and (x+b)\displaystyle (x+b)(x+b) values for x would be -a and -b.
