factoring quadratic trinomials: (a+b)^2-c(a+b)-2c^2 and

[PixelZombie]

how do you factor using c negative factoring pattern?

(a+b)^2-c(a+b)-2c^2

and this with factoring pattern ax^2+bx+c.

(y^2+3y-1)^2-9

 

[Loren]

Re: factoring quadratic trinomials

Are you not seeing the pattern m[sup:32e2pw92]2[/sup:32e2pw92] - mn - 2n[sup:32e2pw92]2[/sup:32e2pw92] = (m + n)(m - 2n) where m is a binomial itself?

 

[fasteddie65]

Re: factoring quadratic trinomials

and this with factoring pattern ax^2+bx+c.

(y^2+3y-1)^2-9

Isn't this just a difference of squares?

(y^2 + 3y - 1)^2 - 3^2 = [(y^2 + 3y - 1) + 3][(y^2 + 3y - 1) - 3]

Now just simplify.