:?: Can anyone help me factor this completely x squared minus the difference of y-3 squared
E EMouz New member Joined Mar 19, 2007 Messages 2 Mar 19, 2007 #1 :?: Can anyone help me factor this completely x squared minus the difference of y-3 squared
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Mar 19, 2007 #2 EMouz said: x squared minus the difference of y-3 squared Click to expand... Does the above mean the following? . . . . .x^2 - (y - 3)^2 If so, start by applying the "difference of squares" formula you memorized. Then simplify the two factors. Eliz.
EMouz said: x squared minus the difference of y-3 squared Click to expand... Does the above mean the following? . . . . .x^2 - (y - 3)^2 If so, start by applying the "difference of squares" formula you memorized. Then simplify the two factors. Eliz.
E EMouz New member Joined Mar 19, 2007 Messages 2 Mar 19, 2007 #3 yes that equation is right Is this work right is this right x^2-y^2+9
pka Elite Member Joined Jan 29, 2005 Messages 11,971 Mar 19, 2007 #4 \(\displaystyle \L\begin{array}{rcl} a^2 - b^2 & = & (a - b)(a + b) \\ x^2 - \left( {y - 3} \right)^2 & = & \left[ {x - (y - 3)} \right]\left[ {x + (y - 3)} \right] \\ & = & (x - y + 3)(x + y - 3) \\ \end{array}\)
\(\displaystyle \L\begin{array}{rcl} a^2 - b^2 & = & (a - b)(a + b) \\ x^2 - \left( {y - 3} \right)^2 & = & \left[ {x - (y - 3)} \right]\left[ {x + (y - 3)} \right] \\ & = & (x - y + 3)(x + y - 3) \\ \end{array}\)
