Kulla_9289
Junior Member
- Joined
- Apr 18, 2022
- Messages
- 217
You have three easy point on this curve: [imath] (0,2), (\pi, 2), (\pi/2, 6)[/imath]I have a sine curve as attached and was told to find a, b, and c. The amplitude is 4 and the vertical shift is 2. How do you find the period cycle?
[imath]2 = a + b \, sin(c \cdot 0)[/imath]How would you solve it? I substituted and got three equations. After substituting into two of the sine equations, I am stuck.
Since you know the vertical shift (and there is no horizontal (phase) shift), you know where the center line of the graph is. Where does it cross that line? Do you see that that is half a cycle?I have a sine curve as attached and was told to find a, b, and c. The amplitude is 4 and the vertical shift is 2. How do you find the period cycle?
Nope. Do you mean that it is 180 degrees? Then, yes.Do you see that that is half a cycle?
What are nodes?
Do you mean that, if the difference between to crests is x, then the nodes will be x/2? x/2 = π. So, x = 2π, which is the period.