You should've seen this in high school.
I'll do one and you attempt the other. OK?.
We want the form y=mx+b, where m is ther slope and b is the y-intercept.
All you have to do is solve them for y, as I said previously.
\(\displaystyle \L\\-9x+8y=22\)
\(\displaystyle \L\\8y=22+9x\)
\(\displaystyle \L\\y=\frac{22+9x}{8}\)
\(\displaystyle \L\\y=\underbrace{\frac{9}{8}}_{\text{slope}}x+\underbrace{\frac{11}{4}}_{\text{y-intercept}}\)
It helps to make a graph also. Have you done that?. The line will intercept the y axis when x=0. Set x=0 in your equation and solve for y.
Also, find the x-intercept by setting y=0 in your equation and solving for x.
You will then have where it crosses the y-axis and the x-axis. You can find the slope from that, too.
Slope = \(\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
\(\displaystyle x_{2} \;\ and \;\ y_{1}\) are 0.
