Fun Math Challenge!

[JohhnyJOhhny]

Find the exact value of the gradient of the tangent to the curve: f(x)=3e^(-x) -2 at the point where x=5!

 

[Steven G]

Yes, that is surely a fun problem!

What result did you get for the answer? I always like to compare my answers to others.

 

[HallsofIvy]

What is the derivative of \(\displaystyle f(x)= 3e^{-x}- 2\) at x= 5?

 

[pka]

Find the exact value of the gradient of the tangent to the curve: f(x)=3e^(-x) -2 at the point where x=5!

\(f(x)=3e^{-x}-2\) you are asked to find the tangent at \((5,f(5))=\)\(\left( {5,\dfrac{3}{{{e^5}}} - 2} \right)\)
Slope will be \(\mathop {\lim }\limits_{h \to 0} \dfrac{{f(5 + h) - f(5)}}{h}\)

 

[Deleted member 4993]

Find the exact value of the gradient of the tangent to the curve: f(x)=3e^(-x) -2 at the point where x=5!

Must not have been any FUN for you - did not do any work worth sharing!!!