Functions

anchovy

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Oct 3, 2021
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14
Hi, I did all of these problems already, but can someone check them for me.
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Quite a list of laundry, there … have you tried anything with any of these?

Recommend you check out the rules for posting.

 
Quite a list of laundry, there … have you tried anything with any of these?

Recommend you check out the rules for posting.

I've tried all of them, the answer under them is what I got.
 
The ones I could do in my head are all correct except for the last one!

Hint: a fraction is not always = 0 when the numerator = 0
 
\(\displaystyle f(x) = 3 + \frac{8}{x - 1}\)

How did you get \(\displaystyle y = 3\)? Can you show me your steps?
 
The ones I could do in my head are all correct except for the last one!

Hint: a fraction is not always = 0 when the numerator = 0
The last one is tricky. I would do this before trying to find the zeros.

\(\displaystyle f(x) = \frac{x^3 - 1}{x^2 + x - 2} = \frac{(x - 1)(x^2 + x + 1)}{(x - 1)(x + 2)}\)
 
I don't think that it is tricky. A fraction equals 0 if the numerator is 0 and the denominator is not 0. Never, and I mean never, say that a fraction equals 0 just because the numerator is zero. If you do so, then you're asking for trouble.
I understand that many students would say that a fraction equals 0 when the numerator equals 0 but simply is not always true.
 
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