As usual, the combination of math and me equals "huh?" If someone to help me think clearly.
The question reads: An isosceles triangle has two angles whose measures are equal. If the third and largest angle of a certain isosceles triangle measures sixty-eight degrees, what are the measures of the other two equal angles?
I know an isosceles has two equal sides or two acute angles, which means they fall somewhere from 0 to 90 degrees. I am told the last angle is 68degrees and I know the acute angles will equal the same but how do I figure them out?
The question reads: An isosceles triangle has two angles whose measures are equal. If the third and largest angle of a certain isosceles triangle measures sixty-eight degrees, what are the measures of the other two equal angles?
I know an isosceles has two equal sides or two acute angles, which means they fall somewhere from 0 to 90 degrees. I am told the last angle is 68degrees and I know the acute angles will equal the same but how do I figure them out?