Geometry

[westin]

Hi, this is a Math Count problem. I am stuck and need some help. Above is what I get so far. thanks!

 

[blamocur]

Looks like you are moving in the right direction. How about areas of BPQC, QRC and PRB ?

 

[westin]

btw, the answer is 2/75

 

[westin]

hi,

area of QRC = area of PRB as PQB and PQC has same area as base and heights are the same. but still I cant see the next step to compare the ratio. what am i still missing?

 

[blamocur]

Please disregard my previous advice. But this hint actually worked for me: what is the height of PQR relative to the height of ABC?

 

[Dr.Peterson]

Think about the relationships of ABC to QBC, of QBC to RBC, and of RBC to PQR.

 

[westin]

got it now. thanks.

let h be height of PQR. then height of BRC = 5h and height of APQ is 3/2h.

then area of ABC = (5x) (15/2h)/2, area of PQR = (x)(h)/2

ratio = (xh) /(75xh/2) = 2/75.

thanks!!