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help again simplifying -5(x-1)< 5(x+1)
- Thread starter cduint
- Start date
i cannot seem to use the inequality symbol in my posts due to technical error. i will substitute by writing it out in regular english. so my problem once again is..-5(x-1) is less than 5(x+1)multiply each side by 1/5...(1-x) is less than (x+1)but why i ask does the (x-1) on the left side of the inequality become (1-x) ???
i cannot seem to use the inequality symbol in my posts due to technical error. i will substitute by writing it out in regular english. so my problem once again is..-5(x-1) is less than 5(x+1)multiply each side by 1/5...(1-x) is less than (x+1)but why i ask does the (x-1) on the left side of the inequality become (1-x) ???
\(\displaystyle \displaystyle{-5(x-1) < 5(x+1)}\)
Multiplied through by \(\displaystyle \displaystyle{\frac15}\)
yields:
\(\displaystyle \displaystyle{-(x-1) < (x+1)}\)
(In your original post there is the negative sign missing!)
\(\displaystyle \displaystyle{-x+1 < x+1~\implies~x > 0}\)