HELP!!!!!!! linear inequalitys

scontreras said:
3x+11< or = 6x+8
Click to expand...
Hint:

Isolate 'x' - like you would in case you are dealing with an "equality"(with only equal sign).

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i have got this far
3x+11< or = 6x+8
-8 -8
3x+3< or = 6x
-6x -6x

-3x+3< or = 0

that is what my teacher told me to do. to get zero on one side
 
3x >= 3

Depending on what the original quest was (which OP has not stated) - you need to go one more step!!
 
scontreras said:
i have got this far
3x+11< or = 6x+8
-8 -8
3x+3< or = 6x
-6x -6x

-3x+3< or = 0

that is what my teacher told me to do. to get zero on one side
Click to expand...
You have not told us what you are supposed to do. if it is to simplify the inequality then you are right as far as you have gone but you can go further.

\(\displaystyle 3x + 11 \le 6x + 8 \implies\)

\(\displaystyle 3x + 11 - 6x - 8 \le 6x + 8 - 6x - 8 \implies\)

\(\displaystyle - 3x + 3 \le 0.\) That is certainly sound, but it may be viewed as incomplete.

\(\displaystyle 3x + 11 \le 6x + 8 \implies\)

\(\displaystyle 3x + 11 - 6x \le 6x + 8 - 6x \implies\)

\(\displaystyle - 3x + 11 \le 8 \implies.\)

\(\displaystyle - 3x + 11 - 11 \le 8 - 11 \implies\)

\(\displaystyle - 3x \le - 3 \implies\)

\(\displaystyle \left(- \dfrac{1}{3}\right) * (- 3x) \ge \left(- \dfrac{1}{3}\right) * - 3 \implies\)

\(\displaystyle x \ge 1.\)

Questions?
 
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