shulmanovsky
New member
- Joined
- Oct 29, 2020
- Messages
- 3
Hi,
I'm not sure i'm posting in the right section...
Anyway, i have an inequality i'm trying to solve forever:
[MATH]\left \lfloor \left | x+1 \right |-\left | x \right | \right \rfloor\geq x^2[/MATH]
I divided it into 4 options:
1. [MATH](x\geq 0)\wedge (x\geq -1)[/MATH]which gives me x is between 0 and 1.
2. [MATH](x\geq 0)\wedge (x< -1)[/MATH]which isn't possible
3. [MATH](x< -1)\wedge (x< 0)[/MATH]which gives me [MATH]x^2\leq -1[/MATH] and it's impossible too
but when i check for [MATH]-1\leq x< 0[/MATH] i get [MATH]\left \lfloor 2x+1 \right \rfloor>x^2[/MATH]i dont know how to continue.
thank you for your help!
I'm not sure i'm posting in the right section...
Anyway, i have an inequality i'm trying to solve forever:
[MATH]\left \lfloor \left | x+1 \right |-\left | x \right | \right \rfloor\geq x^2[/MATH]
I divided it into 4 options:
1. [MATH](x\geq 0)\wedge (x\geq -1)[/MATH]which gives me x is between 0 and 1.
2. [MATH](x\geq 0)\wedge (x< -1)[/MATH]which isn't possible
3. [MATH](x< -1)\wedge (x< 0)[/MATH]which gives me [MATH]x^2\leq -1[/MATH] and it's impossible too
but when i check for [MATH]-1\leq x< 0[/MATH] i get [MATH]\left \lfloor 2x+1 \right \rfloor>x^2[/MATH]i dont know how to continue.
thank you for your help!
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