mandreamorim
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x=2(2-2.3^1/2)/(x-2.3^1/2)
how i can do this?
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Steven G
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Sometimes you just have to think about obvious answers.
You have \(\displaystyle x=\dfrac{2(2-2.3^{1/2})}{(x-2.3^{1/2})}\)
Now what is in the parentheses will cancel out to 1 if x=2. But that is great because both the lhs and the rhs will both equal 2 when x is 2. So the answer x=2. Note that it is a coincident that both sides equal 2 when x=2.
There may be another solution but again you should immediately see that x=2 works.
You have \(\displaystyle x=\dfrac{2(2-2.3^{1/2})}{(x-2.3^{1/2})}\)
Now what is in the parentheses will cancel out to 1 if x=2. But that is great because both the lhs and the rhs will both equal 2 when x is 2. So the answer x=2. Note that it is a coincident that both sides equal 2 when x=2.
There may be another solution but again you should immediately see that x=2 works.
Dr.Peterson
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It may help to temporarily define [MATH]a = 2.3^{1/2}[/MATH], so that the equation becomes [MATH]x=\dfrac{2(2-a)}{x-a}[/MATH]. This will be easier to work with, and in the end you can replace [MATH]a[/MATH] with its value.
Then try multiplying both sides by the denominator to clear fractions before you do anything else.