dollyayesha2345
Junior Member
- Joined
- Oct 28, 2021
- Messages
- 57
If sinx=cosx then find the value of 2tanx−cos2x.
My attempt:
cos xsin x=cos xcos xtanx=1x=tan−1x=45°Substituting x=45° in 2tanx−cos2x2tan45°−cos2(45°)2tan45°−cos90° (I received a feedback saying "wrong solution" on this step exactly)
=2(1)−0=2
My attempt:
cos xsin x=cos xcos xtanx=1x=tan−1x=45°Substituting x=45° in 2tanx−cos2x2tan45°−cos2(45°)2tan45°−cos90° (I received a feedback saying "wrong solution" on this step exactly)
=2(1)−0=2
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