there is only one, where cos a is negative. I just don't understand why.With the given interval and the given ratio, you may have two sets of answers that you need to report: one for values in the 1st quad., and one for values in the 2nd quad.
Please post the EXACT problem. If it is a part of a bigger problem, post the bigger problem.there is only one, where cos a is negative. I just don't understand why.
It is not a part of a bigger problem. This is posted exactly as it is written, I promise.Please post the EXACT problem. If it is a part of a bigger problem, post the bigger problem.
Sometimes the answer lies in the "physics" of the problem.
What are the two angles you get with the given sine? Are they both in the required interval?there is only one, where cos a is negative. I just don't understand why.
so sin a = 5/13 which is about 0,4. One angle I would put between Pi/2 and Pi/4, second angle I would put between Pi and Pi/2...What are the two angles you get with the given sine? Are they both in the required interval?
Or, without actually finding the angles, can you tell from the sine whether they are in that interval?
Really? Is there an angle between pi/4 and pi/2 with that sine? What is the sine of pi/4?so sin a = 5/13 which is about 0,4. One angle I would put between Pi/2 and Pi/4, second angle I would put between Pi and Pi/2...
What helps me to understand signs of trig functions is looking at their actual graphs, not unit circles.I need to determine cos a, tan a and cot a if I know sin a = 5/13 with a being from pi/4 to pi... I know how to determine cos, tan and cot, but I don't know how to determine is cos is positive or negative due to alpha's interval... What do I do?
View attachment 30828
I got confused.Really? Is there an angle between pi/4 and pi/2 with that sine? What is the sine of pi/4?
50-39 = 110?I need to determine cos a, tan a and cot a if I know sin a = 5/13 with a being from pi/4 to pi... I know how to determine cos, tan and cot, but I don't know how to determine is cos is positive or negative due to alpha's interval... What do I do?
View attachment 30828
It should be 04 yeah, the rest are correct, it's just how I divide numbers.50-39 = 110?
110-104=16? I thought that 120-104 = 16, so 110-104 can't also equal 14.