I proved the cosine subtraction formula, but I don't know why it is correct

Four Muffins

New member
Joined
Jun 29, 2022
Messages
25
Hello again. I got stuck for a while on proving [imath]cos(\alpha-\beta) = cos \alpha cos\beta+sin\alpha sin\beta[/imath]. I did solve it, but only by doing something that seems obviously wrong.

With the Cosine Law, [imath]c^2=a^2+b^2-2ab*cos(\theta)[/imath], I normally set [imath]c[/imath] to be the hypotenuse. The triangle in the question has the shortest side of an isosceles triangle as [imath]c[/imath], so I set one of the equal sides to be the pseudo-hypotenuse [imath]b[/imath] and solved for [imath]c[/imath], getting [imath]c^2=b^2-a^2+2ab*cos(\alpha -\beta)[/imath], which did not let me prove the formula.

Does the Cosine Law allow for solving any one unknown side without algebraic manipulation, or am I missing something about what [imath]c[/imath] is in this triangle?

1675922622714.png

Correct, then incorrect working.
20230209_164526.jpg

20230209_164532.jpg
 
The cosine law can be used to solve for the length of an unknown side of any triangle as long as one has the angle opposite to that side and the lengths of the two sides adjacent to that unknown side.

From the diagram’s hint …

[imath]c^2 = 1^2 + 1^2 - 2(1)(1) \cdot \cos(\alpha - \beta)[/imath]

[imath]c^2 = (\cos{\alpha}-\cos{\beta})^2 + (\sin{\alpha}-\sin{\beta})^2[/imath]
 
The cosine law can be used to solve for the length of an unknown side of any triangle as long as one has the angle opposite to that side and the lengths of the two sides adjacent to that unknown side.

From the diagram’s hint …

[imath]c^2 = 1^2 + 1^2 - 2(1)(1) \cdot \cos(\alpha - \beta)[/imath]

[imath]c^2 = (\cos{\alpha}-\cos{\beta})^2 + (\sin{\alpha}-\sin{\beta})^2[/imath]

Thank you Skeeter, that makes sense. I was under the impression that the Cosine Law had to follow the same rules as Pythagoras' Theorum.

Why do you think your solution is wrong?

I didn't think it was wrong, I just didn't understand why it was right. I did a thing I thought was incorrect to get the right answer, and I wasn't sure what I was misunderstanding.
 
Top