If someone can show me process how to get second from first equation.

[ma-ka-01]

(2x²-2x+1)²+1-(4x-2)(2x²-2x+1)(2x-1)=0
Answer: (how to get it??)
−4x(x−1)(3x²−3x+2)

 

[Dr.Peterson]

You probably just have to expand it to a quartic, then recognize that 0 and 1 are zeros and divide out the corresponding factors. There may not be a shortcut.