\(\displaystyle \begin{align*}x+1&<0\text{ given} \\2x+2&<0\text{ multiply by }2\\2x&<-2\text{ subtract }2\\2x&<-2<1\\2x-1&<0\text{ subtract }1\text{ substract } \end{align*}\)if x+1<0, show that
a) 2x-1<0
Another way: First solve the given inequality for x, then multiply the resulting inequality by 2 and subtract 1 in order to get 2x-1 on the left-hand side. Then observe that if 2x-1 < -3, it is also less than 0, so (a) is implied by the original. (It is not stated that the inequalities should be equivalent, only that one implies the other.)if x+1<0, show that
a) 2x-1<0
b) (2x-1)/(x+1) >2
How to do this question , pls help me. Thanks.