James10492
Junior Member
- Joined
- May 17, 2020
- Messages
- 50
Hi there, I am stuck on this problem and would very grateful if someone could help me out.
∫ 10 (axa) dx = a/a+1
I don't know how this solution has been arrived at. When I try myself I get aa+1/a+1 (because a times 0 is zero, and anything divided by zero is zero, so the value of the lower bound is neutral).
This is how I have solved all definite integration problems up to now. What am I doing wrong?
∫ 10 (axa) dx = a/a+1
I don't know how this solution has been arrived at. When I try myself I get aa+1/a+1 (because a times 0 is zero, and anything divided by zero is zero, so the value of the lower bound is neutral).
This is how I have solved all definite integration problems up to now. What am I doing wrong?