is this factorable?

spacewater

Junior Member
Joined
Jul 10, 2009
Messages
67
problem
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)

steps
\(\displaystyle f(x)= 3(x^2-4x+1)\)

this is farthest i got. How can I factor this problem?
 
spacewater said:
problem
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)

steps
\(\displaystyle f(x)= 3(x^2-4x+1)\) ? This function has real but irrational roots. That means this function can be factored - but not with "nice" rational numbers.

this is farthest i got. How can I factor this problem?
 
spacewater said:
problem
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)
steps
\(\displaystyle f(x)= 3(x^2-4x+1)\)
It is not too bad.
\(\displaystyle 3(x^4-4x+1)=3(x-2-\sqrt{3})(x-2+\sqrt{3})\)
 
spacewater said:
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)

How can I factor this problem?
Do the instructions specify that you must factor to find the zeroes? Or are you allowed to use the Quadratic Formula instead? :?:
 
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