JeckShirauw
New member
- Joined
- May 28, 2020
- Messages
- 16
Could someone please explain to me why
lim x^x
x->0
=
lim ln(x^x)
x->0
?
Thank you in advance.
lim x^x
x->0
=
lim ln(x^x)
x->0
?
Thank you in advance.
lim x^x
x->0
\(\mathop {\lim }\limits_{x \to {0^ + }} {x^x} = \mathop {\lim }\limits_{x \to {0^ + }} \exp \left( {\log \left( {{x^x}} \right)} \right) = \exp \left( {\mathop {\lim }\limits_{x \to {0^ + }} \log \left( {{x^x}} \right)} \right) = \exp \left( {\mathop {\lim }\limits_{x \to {0^ + }} \frac{{\log \left( x \right)}}{{1/x}}} \right) = ?\)Could someone please explain to me why
lim x^x
x->0
Thank you!For the record,
lim x^x
x->0
=
lim ln(x^x)
x->0
is NOT true. Those two limits are not equal.