Linear Algebra Question
- Thread starter 5060Jon
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pka
Elite Member
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- Jan 29, 2005
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To 5060Jon, your notation is sloppy in the extreme; I would not give you any credit for it.
Moreover, why did you answer the replies to your other post?
You should now that \(\|\vec{v}\|^2=\vec{v}\cdot\vec{v}\).
\((\vec{u}-\vec{v})\cdot(2\vec{u}-3\vec{v})=2\vec{u}\cdot\vec{u}-3\vec{u}\cdot\vec{v}-2\vec{u}\cdot\vec{v}+3\vec{v}\cdot\vec{v}\)
Can you post more answers?
Moreover, why did you answer the replies to your other post?
You should now that \(\|\vec{v}\|^2=\vec{v}\cdot\vec{v}\).
\((\vec{u}-\vec{v})\cdot(2\vec{u}-3\vec{v})=2\vec{u}\cdot\vec{u}-3\vec{u}\cdot\vec{v}-2\vec{u}\cdot\vec{v}+3\vec{v}\cdot\vec{v}\)
Can you post more answers?
Thank you for the comment on the quality of my notation. my writing (though apparently extremely sloppy), looks the same as what you have written, does this mean that I am doing it correctly. To me, this is a new concept and I am just trying to learn. maybe you could show me the correct notation