treefairy2
New member
- Joined
- Oct 18, 2020
- Messages
- 2
I'm asked to prove that the nth maclaurin polynomial for a function f(x^2) is equal to the 2*nth maclaurin polynomial for another function g(x). I have tried to write out the equation with for instance n=2 which gives me:
(g''''0/4!)*x^4 + (g'''0/3!)*x^3 + (g''0/2!)*x^2 + g'0*x + g(0) = (f''0/2!)*x^4 + f'0*x^2 + f(0)
Which is obviously not right. I fail to see how else I might go about proving this?
Thank you in advance for any help you might be able to provide,
(g''''0/4!)*x^4 + (g'''0/3!)*x^3 + (g''0/2!)*x^2 + g'0*x + g(0) = (f''0/2!)*x^4 + f'0*x^2 + f(0)
Which is obviously not right. I fail to see how else I might go about proving this?
Thank you in advance for any help you might be able to provide,