TheWrathOfMath
Junior Member
- Joined
- Mar 31, 2022
- Messages
- 162
Solve (find all solutions): (2i) ^9*z^3=(1+i) ^17, z=complex number.
When I convert to polar form and solve, I get z^3=sqrt(2)/2*cis(-45).
When I use algebric form, I get z^3=1/2-(1/2)i (which is NOT equivalent to the above polar form).
Why is that?
When I convert to polar form and solve, I get z^3=sqrt(2)/2*cis(-45).
When I use algebric form, I get z^3=1/2-(1/2)i (which is NOT equivalent to the above polar form).
Why is that?