needing help working with negative exponents

[algebradummie]

Is anybody available right now to help me out with these?
on aim, or msn?
or possibly on here?
any help at all i would appreciate so much.

thank you!

 

[arthur ohlsten]

a^-m=a^m

2^1=2
2%0=1
2^-1=1/2
2^-2=1/4
2^-m=1/2^m
Arthur

 

[stapel]

Is anybody available right now to help me out with these?
on aim, or msn?

I'm sorry, but if you are needing immediate private (personal, one-on-one) tutoring, as you have requested, then you would need to contract with a service that offers such. Please note that many (most?) of such "services" are of dubious legitimacy. Caution with credit-card information is strongly recommended.

or possibly on here?

The reason help is offered here at FreeMathHelp is that it is possible to obtain math help here. I apologize for any confusion.

For information on how to post your questions, please read the "Read Before Posting!" thread at the top of this forum.

Thank you.

Eliz.