please find the answer with solution

[vincent_vangogh]

If a and b are members of integers, find the values of a and b in the equation below:

a + b + ab = 16

 

[blamocur]

From Read Before Posting: Show your beginning work, or ask a specific question about the exercise, or explain why you're stuck.

 

[BigBeachBanana]

Nice little problem.
Hint: [imath]a+b+ab+k=16+k\\ \text{choose k such that we can factor the left hand side}\\[/imath]

 

[Steven G]

Nice little problem.
Hint: [imath]a+b+ab+k=16+k\\ \text{choose k such that we can factor the left hand side}\\[/imath]

Brilliant!

 

[Steven G]

a and b are both even. Do you see why?

 

[AvgStudent]

Nice little problem.
Hint: [imath]a+b+ab+k=16+k\\ \text{choose k such that we can factor the left hand side}\\[/imath]

It took me a while, but that was brilliant.

 

[Deleted member 4993]

If a and b are members of integers, find the values of a and b in the equation below:

a + b + ab = 16

Look at the DEFINITION of integer - carefully!!

 

[lookagain]

It took me a while, ...

I don't wish you to post any work, except to ask how many different values of a you got, and how many different values
of b you got. I worked this problem a different way than was referred to in post # 3. I got 4 different values for a and 4
different values for b.

 

[AvgStudent]

I don't want you to post any work, except to state how many different values of a you got, and how many different values
of b you got. I worked this problem a different way than was referred to in post # 3. I got 4 different values for a and 4
different values for b.

I got 4 pairs of solutions.

 

[Steven G]

0 and 16 works!!!