Please help

Albi

Junior Member
Joined
May 9, 2020
Messages
145
If f(2x-3)=2x-1800 then how much is f(2019) going to be?
 
If f(2x-3)=2x-1800 then how much is f(2019) going to be?
What did the function do to 2x-3 so that it became 2x-1800?
If we can assume that the same thing would happen to 2019, then you can easily calculate it.
 
Come on solve 2x-3 = 2019 for x. I am sure that you can do that!
 
Come on solve 2x-3 = 2019 for x. I am sure that you can do that!
There were also some options given to the problem which i didn't write initialy but I am going to tell them now
A 422
B 222
C 402
D 202
 
If 2x-3 = 2019, then f(2019) = f(2x-3).

I have a question for you. You are given that f(2x-3) = 2x-1800. Note then when x=5, 2x-3 = 7. Can you tell us what f(7) equals?? This is the key part! So what is f(7) =?
 
If 2x-3 = 2019, then f(2019) = f(2x-3).

I have a question for you. You are given that f(2x-3) = 2x-1800. Note then when x=5, 2x-3 = 7. Can you tell us what f(7) equals?? This is the key part! So what is f(7) =?
I think i did figure it out I sovled 2x-3=2019 for 'x' and then I pluged that x to 2x-1800 and the result is 222
 
Yes, you were asked repeatedly to solve 2x- 3= 2019 and complained that you couldn't do it!
 
Yes, you were asked repeatedly to solve 2x- 3= 2019 and complained that you couldn't do it!
I hezitated to solve it because I didn't understand was being requested in the problem.
Anyway in the end I managed to solve it.
 
Yes, then you plug 1011 to 2x-1800 and you find the result
Yes I can, however, I can't sit your exams and I can't build your own confidence by doing it all for you. It's not rocket science to put 1011 into 2x-1800 and = something?
 
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