We need to prove that <AYX equals <BYX
we know that <ACB=<AYB=<AYX+<BYX because they are on the same arc
the same goes for<CAY=<CBY same arc of circle
<CAB+<ABC=<YAB+<ABY from <ACB=<AYB but it gives this<CAY=<CBY
is there anyhtong we can gain from <AIX=90 degrees or with inscribed circle?
i also tried to for something with other angles but it didn’t do that muchany ideas how to prove it?