I need some help on a series of problems. This is part of a project. I am to use the following method for solving a quadratic equation and I am getting very confused when I get to part (d). I will write out the entire method, and I would greatly appreciate any and all help I can get.
a. Move the constant term to to the right side of the equation
b. Multiply each term in the equation by four times the coefficient of the x squared term.
c. Square the coefficient of the original x term and add it to both sides of the equation.
d. Take the square root of both sides.
e. Set the left side of the equation equal to the positive square root of the equation and solve for x
f. Set teh left side equal to the negative of the square root and solve for x.
this is the example they gave me.
solve x^+3x-10=0
x^+3x=10
4x^+12x=40
4x^+12x+9=40+9
4x^+12x+9=49
2x+3=+-7
2x+3=7 and 2x+3=-7
2x=4 2x=-10
x=2 x=-5
This seemed simple enough, but when I started trying it on my own with the problems they gave me, I am having a very difficult time. Below is listed one of the problems given. Can someone help me solve this, and give a little more detail when it gets to taking the square of both sides. I would greatly appreciat it. Thank you soooo much.
x^-2x-13=0
a. Move the constant term to to the right side of the equation
b. Multiply each term in the equation by four times the coefficient of the x squared term.
c. Square the coefficient of the original x term and add it to both sides of the equation.
d. Take the square root of both sides.
e. Set the left side of the equation equal to the positive square root of the equation and solve for x
f. Set teh left side equal to the negative of the square root and solve for x.
this is the example they gave me.
solve x^+3x-10=0
x^+3x=10
4x^+12x=40
4x^+12x+9=40+9
4x^+12x+9=49
2x+3=+-7
2x+3=7 and 2x+3=-7
2x=4 2x=-10
x=2 x=-5
This seemed simple enough, but when I started trying it on my own with the problems they gave me, I am having a very difficult time. Below is listed one of the problems given. Can someone help me solve this, and give a little more detail when it gets to taking the square of both sides. I would greatly appreciat it. Thank you soooo much.
x^-2x-13=0