Bobby Jones
New member
- Joined
- Jul 8, 2011
- Messages
- 41
Morning people, Ive been asked to find the quadratic roots of 65.53-j47.61, I need to express the answer in rectangular form to 3 decimal places.
First I turned 65.53-j47.61 into polar form which makes: 81<324 degrees.
From here do I simply add and takeaway 90 degrees from 324 so I'd get
81<234 degrees
81<144 degrees
81<54 degrees
I'm very stuck as this dosent seem correct.
First I turned 65.53-j47.61 into polar form which makes: 81<324 degrees.
From here do I simply add and takeaway 90 degrees from 324 so I'd get
81<234 degrees
81<144 degrees
81<54 degrees
I'm very stuck as this dosent seem correct.