petarantes
New member
- Joined
- Oct 21, 2016
- Messages
- 15
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That form is considerably clearer, connecting them with "or". It troubles me when I see students list inequalities without indicating how they are to be combined. I suppose I can forgive software for doing that.HI Dr. Peterson and Jomo.
The objective is clear, to solve the inequality, It is not to prove <1. It's in the title. It is a book issue.
The solution is from the wolfram website but I am putting the solution ((attachment) in the book which is the same as the website. (..."But it seems odd that there are two cases both of which say a>2 "...)
See that the book solution put the two cases together> 2.
That's more like it.Dr. Peteson
EDIT: On glancing through the details, I see that the second and third lines in the D box were solved incorrectly, as if the log weren't there
Second line: [MATH]log_a \frac{3-2x}{1-x} \geq 0 \rightarrow \frac{3-2x}{1-x} \geq 1 \rightarrow x < 1~or~\geq 2 \rightarrow a > 1, x \neq 1[/MATH]
Third line: [MATH]log_a \frac{3-2x}{1-x} \geq 0 \rightarrow \frac{3-2x}{1-x} \leq 1 \rightarrow 1 < x \leq 2\rightarrow 0 < a < 1, x \neq 1 [/MATH]
As no one was able to solve it I will post the solution I found. It is not an easy exercise.