Re: saxon problem
Hello, john deere!
Exactly where is your difficulty?
Let \(\displaystyle x\) = the number.
\(\displaystyle \underbrace{\text{A number is multiplied by 7}}_{\downarrow}\;\text{and}\;\underbrace{\text{increased by 42}}_{\downarrow}\)
. . . . . . . . . . .\(\displaystyle \overbrace{7x}\) . . . . . . . . . . . . . . . . . . .\(\displaystyle \overbrace{+\;\;42}\)
\(\displaystyle \underbrace{\text{the result is}}_{\downarrow}\;\underbrace{\text{87 greater than}}_{\downarrow}\;\underbrace{\text{twice the opposite of the number}}_{\downarrow}\)
. . . . .\(\displaystyle =\) . . . . . . . . \(\displaystyle \overbrace{87\;\;\;+}\) . . . . . . . . . . . . . . . .\(\displaystyle \overbrace{2(-x)}\)
There is our equation! \(\displaystyle \:7x\,+\,42\;=\;87 \,-\,2x\)
