Series function

[Loki123]

I have no idea what to do here. I have no Gn(x) function so I would just keep going forever by doing n+1. What do I do?

 

[BigBeachBanana]

I have no idea what to do here. I have no Gn(x) function so I would just keep going forever by doing n+1. What do I do? View attachment 32561

Write out the first 6 in terms of x. Do you see a pattern?

 

[topsquark]

I have no idea what to do here. I have no Gn(x) function so I would just keep going forever by doing n+1. What do I do? View attachment 32561

Work these out to [imath]g_4(x)[/imath]. What happens?

-Dan

 

[Loki123]

Work these out to [imath]g_4(x)[/imath]. What happens?

-Dan

Write out the first 6 in terms of x. Do you see a pattern?

Three values keep repeating

 

[BigBeachBanana]

Three values keep repeating
View attachment 32578

Ok, continue. What do you think is the value of [imath]g_{2013}?[/imath]

 

[Loki123]

Ok, continue. What do you think is the value of [imath]g_{2013}?[/imath]

well the values repeat every 3 function. g3 and g6 are the same. 2013 is divisible by 3. so I would assume I could use g3 for it. so it would be 1/2013 or 2013^(-1). Am I correct?

 

[BigBeachBanana]

well the values repeat every 3 function. g3 and g6 are the same. 2013 is divisible by 3. so I would assume I could use g3 for it. so it would be 1/2013 or 2013^(-1). Am I correct?

Yes,