Show dV/dt = -kV^2/3 given.......

donal1353

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Mar 29, 2024
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Hi, im having trouble with a "show" style question that forms part 1 of a multi part question, I have no problems with the rest if I take the "show" stage to be absolutly true. Some general guidance regarding the process would be appreciated. The question is as follows:

A spherical pill with volume V and surface area S is swallowed and slowly dissolves in the stomach. Assume that the rate of decrease in the volume V is directly proportional to the pill's surface area.

a)i)
Show dV/dt = -kV^2/3 , where K is the constant of proportionality and k > 0.
 
Hi, im having trouble with a "show" style question that forms part 1 of a multi part question, I have no problems with the rest if I take the "show" stage to be absolutly true. Some general guidance regarding the process would be appreciated. The question is as follows:

A spherical pill with volume V and surface area S is swallowed and slowly dissolves in the stomach. Assume that the rate of decrease in the volume V is directly proportional to the pill's surface area.

a)i)
Show dV/dt = -kV^2/3 , where K is the constant of proportionality and k > 0.
Volume of a sphere (of radius = r) = 4/3 * (pi) * r^3 and .......... Surface area of a sphere (of radius = r) = ??

As the pill gets dissolved - does it maintain "spherical" geometry?
 
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