I am struggling to understand why my answer is different from the actual answer to this simple formula rearrangement:
Make x the subject:
Q) v = (2/3)x - 2
Actual answer) x = (3v + 6) / 2
My answer) x = (3v + 2) / 2
My revision guide states to get rid of the fraction before anything else and then rearrange. So my working is:
step 1) 3v = 2x - 2
step 2) move the -2 to the other side = 3v + 2 = 2x
step 3) divide by 2 = (3v + 2) / 2 = x
To get the actual answer it's apparent that the 2 was moved to the opposite side first.
Can someone please clarify this for me. Thanks.
Make x the subject:
Q) v = (2/3)x - 2
Actual answer) x = (3v + 6) / 2
My answer) x = (3v + 2) / 2
My revision guide states to get rid of the fraction before anything else and then rearrange. So my working is:
step 1) 3v = 2x - 2
step 2) move the -2 to the other side = 3v + 2 = 2x
step 3) divide by 2 = (3v + 2) / 2 = x
To get the actual answer it's apparent that the 2 was moved to the opposite side first.
Can someone please clarify this for me. Thanks.