Simplifying Issue

[mrhmaths]

Hi Folks! Please see my problem above. I am ok with taking out the common factor for step 2 but I can't get my head around how it simplifies to the final step. I understand I am multiplying the terms inside the brackets by 4 to get rid of the denominator, but why am I dividing the outside term by 2? Any help at all would be appreciated. Thanks in advance for any consideration

 

[Harry_the_cat]

It is incorrect. The 2 should be a 4.

 

[Cubist]

it would be correct with the addition of some parenthesis, like this...

[math] r^2 \left(16-\frac{\pi}{4}\right)[/math]
[math] =\left(\frac{r}{2}\right)^2 \left(64-\pi\right)[/math]

 

[Steven G]

it would be correct with the addition of some parenthesis, like this...

[math] r^2 \left(16-\frac{\pi}{4}\right)[/math]
[math] =\left(\frac{r}{2}\right)^2 \left(64-\pi\right)[/math]

I never liked parenthesis, they always get in the way of my getting high grades

 

[Cubist]

I never liked parenthesis, they always get in the way of my getting high grades

Yes, it's usually a very bad idea to let your parents write your final report, therefore a "parent-thesis" would indeed result in a lower grade

 

[mrhmaths]

it would be correct with the addition of some parenthesis, like this...

[math] r^2 \left(16-\frac{\pi}{4}\right)[/math]
[math] =\left(\frac{r}{2}\right)^2 \left(64-\pi\right)[/math]

Ma

it would be correct with the addition of some parenthesis, like this...

[math] r^2 \left(16-\frac{\pi}{4}\right)[/math]
[math] =\left(\frac{r}{2}\right)^2 \left(64-\pi\right)[/math]

Makes total sense thank you ?

 

[mrhmaths]

Much appreciated people! You have made things very clear! God bless you and your parents and their thesis(s)