-(9/5)x dived by 5 is not x.Is it that I can divide by 5
Yes.We can divide in this case by 3
Ok. Can you simplify the left hand side?
Maybe not simplify - convert to whatever form acceptable in your class. E.g. I would do something about the fraction in the denominator.I'm not sure how it can be simplified further
No, this is not correct. You had \(\displaystyle \dfrac{-9x}{5}\). Now if you compute \(\displaystyle \dfrac{\dfrac{-9x}{5}} {\dfrac{9}{5}}\) you get -x, not x.
I think it is -9/5.No, this is not correct. You had \(\displaystyle \dfrac{-9x}{5}\). Now if you compute \(\displaystyle \dfrac{\dfrac{-9x}{5}} {\dfrac{9}{5}}\) you get -x, not x.
You should either divide by \(\displaystyle \dfrac{-9}{5}\) or multiply by \(\displaystyle \dfrac{-5}{9}\)
First of all, you need parentheses around y-8.How about
x = y - 8 / - (9/5)
Please read post #7 and your reply in post #8 where you said all was good.I think it is -9/5.
OP divided LHS by -9/5, confirmed by post 11. The negative sign is there, in front of the fraction bar.Please read post #7 and your reply in post #8 where you said all was good.
I thought that might have been the case! Have a great day!OP divided LHS by -9/5, confirmed by post 11. The negative sign is there, in front of the fraction bar.