solving 7/8 (x-2) + 3/4 - 1/8x

[nsdragonlady]

I've tried to solve this by finding the lcm for 3/4 with would be 8 making the fraction 6/8, then I tried to combine like terms. My problem here is solving for two variables of x. I'm so confused. HELP.

7/8 (x-2) + 3/4 - 1/8x

I end up with 19/8, but I think it should end up as 20/8 then reduced to 5/2. But how do I get there? :evil:

 

[stapel]

Since you have not provided the "equals" sign and whatever was given as being on the other side of it (that is, the rest of the equation), it is not possible to solve this. Sorry.

Note: Your formatting is ambiguous. What you have posted could mean any of the following:

. . . . .7 / [8(x - 2)] + 3/4 - 1 / [8x]

. . . . .(7/8)(x - 2) + 3/4 - (1/8)x

. . . . .7 / [8(x - 2) + 3/4] - (1/8)x

There are probably other interpretations as well. Which did you mean?

Please reply with the rest of this equation, along with a clear listing of the steps and reasoning you used to arrive at your solution value for x.

Thank you.

Eliz.

 

[nsdragonlady]

Sorry Stapel, typing error on my part

7/8 (x-2) = 3/4 - 1/8x

 

[Denis]

Sorry Stapel, typing error on my part
7/8 (x-2) = 3/4 - 1/8x

rewrite:
7(x - 2) / 8 = 3/4 - x/8; apply LCD 8:
7(x - 2) = 6 - x

OK?

 

[stapel]

Sorry Stapel, typing error on my part

7/8 (x-2) = 3/4 - 1/8x

Okay; that clarifies where the "equals" sign is. However, your formatting retains the aforementioned ambiguity. Please reply with the requested clarification, if the other tutor hasn't guessed your meaning correctly.

Thank you.

Eliz.